这种json应该怎样取出呢

welking

[{"0":"5568","id":"5568","1":"10","sl":"10","2":"13980081728","user":"13980081728"},{"0":"5570","id":"5570","1":"10","sl":"10","2":"18980130776","user":"18980130776"},{"0":"5595","id":"5595","1":"70","sl":"70","2":"13091647636","user":"13091647636"},{"0":"5596","id":"5596","1":"100","sl":"100","2":"18903643176","user":"18903643176"},{"0":"5599","id":"5599","1":"100","sl":"100","2":"13760821581","user":"13760821581"},{"0":"5600","id":"5600","1":"100","sl":"100","2":"13029762877","user":"13029762877"},{"0":"5601","id":"5601","1":"30","sl":"30","2":"18742269377","user":"18742269377"},{"0":"5602","id":"5602","1":"100","sl":"100","2":"15899221878","user":"15899221878"},{"0":"5603","id":"5603","1":"50","sl":"50","2":"13326758613","user":"13326758613"}]

我想要取出id ，sl ，user的值
数组不知道应该怎么写了 ，感觉这个不是标准的json
忘记说了，是E4A代码

新手 不懂这种取的方式  望指教

LEH234

JSON.取通用属性 (“[6].user”)

yudave

就来看看了

welking

LEH234 发表于 2020-4-17 11:14
JSON.取通用属性 (“[6].user”)

首先感谢回复 ！
我想要取出id ，sl ，user的值
数组不知道应该怎么写了 ，感觉这个不是标准的json
忘记说了 是E4A代码

唯独♂奇光

{"0":"(.*?)","id":"(.*?)","1":"(.*?)","sl":"(.*?)","2":"(.*?)","user":"(.*?)"}
用正则吧

welking

唯独♂奇光 发表于 2020-4-17 14:46
{"0":"(.*?)","id":"(.*?)","1":"(.*?)","sl":"(.*?)","2":"(.*?)","user":"(.*?)"}
用正则吧

感谢！！！！用你 方法解决了

qanjn

楼上那个好人

jiujusir

你这个缺个json的数组名，数组名[数组]，json解析[数组] json取数组成员数。这样循环遍历就可以了

308750021

LEH234 发表于 2020-4-17 11:14
JSON.取通用属性 (“[6].user”)

什么类库的？